What is the equation of the oblique asymptote? 2 h(x)=x²-x-2 x+1 O A. y=x+1 O B. y=x2+1 O c. y=x-2 O D.y=x

Answer:
Explanations:
To get the equation of the oblique asymptote of a function, we will first have to get the quotient of the given function. Given the function:
[tex]h(x)=\frac{x^2-x-2}{x+1}[/tex]Factoring the numerator and simplifying will give;
[tex]\begin{gathered} h(x)=\frac{x^2-2x+x-2}{x+1} \\ h(x)=\frac{(x^2-2x)+(x-2)}{x+1} \\ h(x)=\frac{x(x-2)+1(x-2)}{x+1} \\ h(x)=\frac{\cancel{(x+1)}(x-2)}{\cancel{x+1}} \\ h(x)=x-2 \end{gathered}[/tex]The equation of the oblique asymptote is the first two terms of the quotient that is x - 2