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A lot is in the shape of a triangle. One side is 300 ft longer than the shortest side, while the third side is 400 ft longer than the shortest side. The perimeter of the lot is 1900 ft. Find the length of the sides of the lot. The lengths of the sides of the lot are __, __, and ___. (ft^2, ft, ft^3)(Simplify your answers. Use ascending order.)

Respuesta :

Let x is a shortest side then other side is:

x+300 and x+400.

Perimeter = 1900

Perimeter of triangle is:

[tex]\begin{gathered} x+(x+300)+(x+400)=1900 \\ x+x+300+x+400=1900 \\ 3x+700=1900 \\ 3x=1900-700 \\ 3x=1200 \\ x=\frac{1200}{3} \\ x=400 \end{gathered}[/tex]

So the sides of triangle is

[tex]\begin{gathered} 1)\rightarrow_{}x=400 \\ 2)\rightarrow x+300=400+300 \\ =700 \\ 3)\rightarrow x+400=400+400 \\ =800 \\ \end{gathered}[/tex]

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