The question is given as
[tex]\frac{2x^2-5x+8}{x+4}[/tex]Perform long division to find the quotient and the remainder
Start with 2x^2 divided by x to get : 2x^2+4
Subtract 2x^2+8x from 2x^2-5x to get -13x+8
Divide -13x +8 by x+4 to get -13 then multiply -13 by x+4 to have -13x-52
perform subtraction of -13x -52 from -13x +8 to get the remainder as 60
The solution is : 2x -13 remainder 60
Answer : A . 60
