BanyanV660063 BanyanV660063

28-10-2022
Mathematics

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Find the zeros of the following quadratic equation:y = x^2-3x-18A.) -3, -6B.) 3, -6C.) 3, 6D.) -3, 6

Respuesta :

NemiahI223645 NemiahI223645

28-10-2022

we have the quadratic equation

[tex]y=x^2-3x-18[/tex]

using the formula

a=1

b=-3

c=-18

substitute given values

[tex]x=\frac{-(-3)(+_-)\sqrt{-3^2-4(1)(-18)}}{2(1)}[/tex][tex]x=\frac{3(_{+\-})9}{2}[/tex]

The values of x are

x=6 and x=-3

the answer is option D

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