First, we need to know the total hours from 9 pm to 6:36 am.
We have that from 9:00 pm to 6:00 am are 9 hours. We still have 36 minutes.
And
[tex]36\min \cdot\frac{1hour}{60\min }=0.6hour[/tex]Then, the total hours are 9.6 hours.
The water level decreased by 6/35 in. Then:
[tex]d=\frac{\frac{6}{35}in}{9.6\text{hour}}\Rightarrow d=0.01786in/\text{hour}[/tex]Then, the level decreased approximately 0.01786 in/hour at that period of time (the water level decreased at a constant rate).