The area of the sector can be detemined as,
[tex]\begin{gathered} A_s=\pi r^2\times(\frac{\theta}{360}) \\ =\pi(10ft)^2\times\frac{300^{\circ}}{360^{\circ}} \\ =100\pi\times\frac{5}{6}ft^2 \\ =\frac{250\pi}{3}ft^2 \end{gathered}[/tex]
Thus,option (D) is the correct solution.
