I’m having trouble on this calculus practice problem Below are the answer options to this problem:A. -2B. 1 C. 3D. The limit does not exist

C. 3
EXPLANATION
When x = -1
Locate the value of h(-1) on the y-axis
From the graph, at x=-1 we have a hole of y=1, which means the limit point do not exist at that point but we also have a point y=3, which means the limit point do exist here and it is 3.
Therefore, limit of h(x) as x tends to -1 is 3