Given data:
The first point is A=(0, 6).
The second point is B=(3, 2).
The equation of the line passing throught the given points is,
[tex]\begin{gathered} y-6=\frac{2-6}{3-0}(x-0) \\ y-6=-\frac{4}{3}x \\ y=-\frac{4}{3}x+6 \end{gathered}[/tex]
Thus, the equation of line in slope intercept form is y=-(4/3)x+6
