Respuesta :
when 0.367 mol of a weak acid, hx, is dissolved in 2.00 l of aqueous solution, the ph of the resultant solution is 2.60. ka for hx is 3.405 × [tex]10^{-5}[/tex]
Number of moles = 0.367
Volume of solution = 2l
concentration = 0.367/2 = 0.1835 mol/L
ph = 2.60
we know
ph = - log [H+]
2.51 × [tex]10^{-2.60}[/tex]M = [H+]
The acid HX dissociate as
HX → H+ + X-
The acid dissociation constant Ka, for the dissociation reaction is
Ka = [H+][X-]/[HX] ; at equilibrium, [H+] = [X-]
Ka = 3.405 × [tex]10^{-5}[/tex]
A solution in which water serves as the solvent is called an aqueous solution. The most common way to represent it in chemical equations is to add (aq) to the appropriate chemical formula. For instance, the formula for a solution of table salt, or sodium chloride (NaCl), in water is Na+(aq) + Cl The word aqueous, which derives from the word aqua, means that something is connected to, resembles, or is dissolved in water. Water is a common solvent in chemistry because it is an excellent solvent and abundant in nature. Since water is frequently used as the experiment's solvent, unless otherwise stated, the term "solution" refers to an aqueous solution.
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