Given data:
Assume the following events:
Event A = person is a doctor
Event B = person is a man
P(A) = 58% are doctors
P(B) = 44% are men
P(A and B) = 43% are male doctors
Find: probability that a random person is a doctor or a man or both (A or B)
Solution:
[tex]\begin{gathered} P(\text{A or B)}=P(A)+P(B)-P(A\text{ and B)} \\ P(A\text{ or B)}=0.58+0.44-0.43 \\ P(A\text{ or B)}=0.59 \end{gathered}[/tex]Answer: The probability that a person selected at random at
this conference is a doctor or man (or both) is 59%.
