contestada

a 0.35 kg softball has a velocity of 11 m/s at an angle of 28 nelow the horizontal just before makig contact with the bat. what is the magnitude of the change in momentum of the ball while it is in contacft with the ball

Respuesta :

onyebuchinnaji

The magnitude of the change in momentum of the ball while it is in contact with the ball is 3.4 kgm/s.

What is the change in momentum of the softball?

The change in the momentum of the soft ball is calculated by applying the principle of conservation of linear momentum as shown below.

Mathematically, change in momentum is given as;

ΔP = Pf - Pi

where;

  • Pf is the final momentum of the ball
  • Pi is the initial momentum of the ball

ΔP = m(Vf - Vi)

where;

  • Vf is the final velocity of the ball = 0
  • Vi is the initial velocity of the ball =  11 m/s

ΔP = -mVi

ΔP =-mViₓ

The initial horizontal velocity (Viₓ)  of the  ball is calculated as;

Viₓ = Vi cosθ

ΔP = -mVi cosθ

ΔP = - (0.35)(11) cos(28)

ΔP = -3.4 kgm/s

magnitude = 3.4 kgm/s

Learn more about change in momentum here: https://brainly.com/question/7538238

#SPJ1

Otras preguntas