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Victor biked from his hometown to a neighboring city in 6 hours. He biked back to his hometown in 4 hours. His speed on the return trip was 4 mph faster than his speed on the first trip. How far apart are the two cities?

Respuesta :

We will have the following:

His speed on the return (r) trio was 4mph faster than his speed in the first trip (o), so:

[tex]r=o+4[/tex]

Then, we have that speed times distance equals time, and distance is equal to time over speed. Thus:

[tex]6h(\frac{x}{\text{hours}})=4h(\frac{x+4}{\text{hours}})[/tex]

Then, we have:

[tex]6x=4x+16\Rightarrow2x=16[/tex][tex]\Rightarrow x=8[/tex]

So, the initial speed was of 8mph.

Then we deternine the distance:

[tex]d=(8mi/h)(6h)\Rightarrow d=48mi[/tex]

So, the two cities are 48 miles apart.

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