Given:
The force applied by the logan is
[tex]F=400\text{ N}[/tex]The force applied by the Andrew is
[tex]F=250\text{ N}[/tex]Required: component of force applied by the andrew.
Explanation:
first, draw the free body diagram,
from the free body diagram we can write resolve the force into two components
one along the y axis and one along the x axis
Along x axis
[tex]F\sin(290^{\circ})[/tex]Plugging the values, we get
[tex]\begin{gathered} =250\times\sin(290) \\ =250\times-0.939 \\ =-234.92\text{ N} \end{gathered}[/tex]Along y axis
[tex]\begin{gathered} F\cos(290^{\circ}) \\ =250\times\cos(290^{\circ}) \\ =250\times0.342 \\ =85.50\text{ N} \end{gathered}[/tex]Thus, the component of forces are
[tex]85.50\text{ N, }-234.92\text{ N}[/tex]and option first is correct.
