You need to solve
[tex]5(2x-8)=20[/tex]First step is to solve the multiplication in parentheses by applying the distributive propperty of multiplications, that is, multiply each term held between them by 5:
[tex]\begin{gathered} 5\cdot2x-8\cdot5=20 \\ 10x-40=20 \end{gathered}[/tex]Next "pass" -40 to the other side of the equation by performing the inverse operation to both of its sides
[tex]\begin{gathered} 10x-40+40=20+40 \\ 10x=60 \end{gathered}[/tex]Finally divide both sides of the equation by 10 to determine the value of x
[tex]\begin{gathered} \frac{10x}{10}=\frac{60}{10} \\ x=6 \end{gathered}[/tex]The vlaue of x is 6
