The given function :
[tex]y=\frac{1}{2}^x[/tex]
Substitute x = 0
[tex]\begin{gathered} y=\frac{1}{2}^0 \\ y=1 \end{gathered}[/tex]
(x,y) = (0,1)
Substitute x =1
[tex]\begin{gathered} y=\frac{1}{2}^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}[/tex]
(x,y) = (1, 0.5)
Substitute x =(-2)
[tex]\begin{gathered} y=\frac{1}{2}^{(-2)} \\ y=\frac{1^{-2}}{2^{-2}}^{} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}[/tex]
So, (x, y) = ( -2, 4)
Substitute x = (-3)
[tex]\begin{gathered} y=\frac{1}{2}^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}[/tex]
So, (x,y) = (-3, 8)
Substitute the value of x = (-1)
[tex]\begin{gathered} y=\frac{1}{2}^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}[/tex]
So, (x, y) = ( -1, 2)
So, the set of coordinates are :
The graph will be :
