p1 ( - 3, 4 ) and p2 ( 5, - 2 )
therefore de distance is
[tex]\begin{gathered} d=\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ d=\sqrt[]{(5-(-3))^2+(-2-4)^2} \\ d=\sqrt[]{(5+3)^2+(-6)^2} \\ d=\sqrt[]{8^2+36} \\ d=\sqrt[]{64+36} \\ d=\sqrt[]{100} \\ d=10 \end{gathered}[/tex]answer: the distance is 10
