A box contains 3 red, 4 black, and 7 green balls. If three balls are drawn one after the other at random with replacement, find the probability that all 3 are red.

Respuesta :

To answer this question we will use the following expression to compute the probability that an event occurs:

[tex]\frac{FavorableOutcomes}{TotalOutcomes}.[/tex]

Since the choice is with replacement, then the probability of choosing a red ball is always the same.

The probability of choosing a red ball is:

[tex]\frac{3}{3+4+7}=\frac{3}{14}.[/tex]

Then the probability of choosing 3 red balls is:

[tex]\frac{3}{14}\times\frac{3}{14}\times\frac{3}{14}=\frac{27}{2744}.[/tex]

Answer:

[tex]\frac{27}{2744}.[/tex]