ANSWER
The mass of AgNO3 contained in the solution is 305.766 grams
EXPLANATION
Given that;
The volume of AgNO3 solution is 3L
The concentration of the solution is 0.6M
Follow the steps below to find the mass of AgNO3
Step 1; Find the number of moles of AgNO3 using the below formula
[tex]\text{ molarity = }\frac{\text{ moles}}{\text{ volume}}[/tex]Substitute the given data into the formula above
[tex]\begin{gathered} \text{ 0.6 = }\frac{\text{ mole}}{3} \\ \text{ cross multiply} \\ \text{ mole = 0.6}\times\text{ 3} \\ \text{ mole = 1.8 mol} \end{gathered}[/tex]Step 2; Find the mass of AgNO3 using the formula below
[tex]\text{ mole }=\text{ }\frac{\text{ mass}}{\text{ molar mass}}[/tex]Recall, that the molar mass of AgNO3 is 169.87 g/mol
[tex]\begin{gathered} \text{ 1.8 }=\text{ }\frac{\text{ mass}}{\text{ 169.87}} \\ \text{ cross multiply} \\ \text{ mass = 1.8 }\times\text{ 169.87} \\ \text{ mass = 305.766 grams} \end{gathered}[/tex]Therefore, the mass of AgNO3 contained in the solution is 305.766 grams
