ANSWER
[tex]\log _87-log_83=log_8\text{ }\frac{7}{3}[/tex]
STEP-BY-STEP EXPLANATION:
Below is the given logarithm function
[tex]\log _87-log_83[/tex]
To simplify this expression, we need to apply the rules of the logarithm
Assuming we have Log A - log B with a common base
[tex]\begin{gathered} \text{According to the law of logarithm} \\ \log _xA-log_xB=\log _x\frac{A}{B}_{} \end{gathered}[/tex]
Hence,
[tex]\text{log}_87-log_83=log_8\frac{7}{3}[/tex]
