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A ship travels 10 km on a course heading 50º east of north. How far north, and how far east has the ship traveled at this point? Draw a picture and show work!

Respuesta :

The ship travels 6.43 km towards north and 7.66 km towards the east from the point where the ship was headed. This can be verified from the Pythagoras theorem.

What is displacement?

Displacement is the change in the position of the ship in water. This can be calculated through trigonometric identities.

According to trigonometric identities we know that:

sinФ = ( side opposite to Ф ) / ( longest side )

Side opposite to 40° is y

Longest side is 10 km

Hence we can write that:

sin 40 = y / 10

sin 40 = 0.641

0.643 = y/10

y = 0.643 × 10

y ≈ 6.43 km

The value of y is approximately 6.43 km

Now we know that by Pythagoras theorem:

x² + y² = 10²

x² + ( 6.43 )² = 100

x² = 100 - 41.345

x² = 58.655

x ≈ 7.66 km

The value of x is approximately 7.66 km

The Pythagoras theorem states:

( longest side )² = ( base )² + ( height )²

The theorem is applied in right angles

sin 40 is 0.641

For verification:

x² + y² = 100

(7.66)² + (6.43)²

100

Learn more about Pythagoras theorem here:

https://brainly.com/question/343682

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