Given:
A geometric sequence is given as 1/27,1/9,1/3,1...
Required:
We have to find the which term is 6561 in this sequence
Explanation:
Here a means the first term is 1/27 and r means ratio is 3
now we have formula for geometric sequence is
[tex]a_n=ar^{n-1}[/tex]here an is 6561
now just put all vales and find the n
[tex]6561=\frac{1}{27}3^{n-1}[/tex][tex]177147=3^{n-1}[/tex][tex]3^{11}=3^{n-1}[/tex][tex]n-1=11[/tex]so
[tex]n=12[/tex]Final answer:
6561 is 12th term
