Respuesta :
The molarity of an acetic acid solution if 25.00 ml of 0.112 m sodium hydroxide solution is required to neutralize 35.00 ml of acetic acid is 0.08M
What is the molarity of acetic acid?
The concentration is provided in percent by mass (w/w), the molarity of concentrated acetic acid (CH3COOH) Acetic acid (CH3COOH) has a molecular weight of 60.05 g/mol.
To neutralize acid and base, moles of acid should be equal to moles of base
Moles of CH3COOH= moles of NaOH
nCH3COOH=n NaOH
(Molarity*Volume)CH3COOH=(Molarity*Volume)NaOH
(Molarity)CH3COOH*35ml=0.112M*25ml
Molarity of CH3COOH=0.112*25/35
=0.08M
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