Help please i couldn’t type problem out see picture its for a study guide i do online classes and my professor said that if we work out problems and get them right we might get points of exam for partaking in this

ANSWER
[tex]h(3a)=\frac{5+3a}{3+9a}[/tex]EXPLANATION
We are given the function:
[tex]h(x)=\frac{5+x}{3+3x}[/tex]We want to find h(3a). To do this, substitute 3a for x in the given function and simplify:
[tex]\begin{gathered} h(3a)=\frac{5+(3a)}{3+3(3a)} \\ h(3a)=\frac{5+3a}{3+9a} \end{gathered}[/tex]That is the value of h(3a).