If we draw both triangles, we get the following:
notice that the transformation on triangle 1 made it smaller, then, we have a dilation.
To find the scale factor, we have to remember the general rule for the dilations on the cartesian plane:
[tex]\begin{gathered} d_k(x,y)=(kx,ky) \\ k\ne0 \end{gathered}[/tex]in this case, we can take the point A' on triangle 2 and the point A on triangle 1 , assuming that the transformation gave us the point on triangle 2:
[tex]\begin{gathered} d_k(6,6)=(2,2) \\ \Rightarrow(6k,6k)=(2,2) \\ \Rightarrow6k=2 \end{gathered}[/tex]solving for k, we get:
[tex]\begin{gathered} 6k=2 \\ \Rightarrow k=\frac{2}{6}=\frac{1}{3} \\ k=\frac{1}{3} \end{gathered}[/tex]therefore, the scale factor is k = 1/3
