Given the formulas below
[tex]\begin{gathered} C=\frac{5}{9}(F-32) \\ F=\frac{9}{5}C+32 \end{gathered}[/tex]
We are to convert 62°F to Celcius using any of the formulas above.
I will going with the first formula
[tex]\begin{gathered} C=\frac{5}{9}(F-32) \\ \text{Where,} \\ F=62^0F \end{gathered}[/tex]
Therefore,
[tex]\begin{gathered} C=\frac{5}{9}(62-32) \\ C=\frac{5}{9}(30) \end{gathered}[/tex]
Simplify
[tex]\begin{gathered} C=\frac{5}{9}(30)=\frac{150}{9}=16.6666667\approx16.7^0(nearest\text{ tenth)} \\ \therefore C=16.7^0 \end{gathered}[/tex]
Hence, the answer is
[tex]16^{}.7^0C[/tex]
