A bird spots a worm on the ground. The bird is 36 feet above the ground and with a horizontal distance of 45 feet to the worm. What is the angle of the bird's view on the worm? Round your answer to the nearest hundredth.

Respuesta :

Let's take a look at the situation:

We know, because of the Pythagorean theorem, that:

[tex]\begin{gathered} d^2=45^2+36^2\rightarrow d=\sqrt[]{45^2+36^2} \\ \rightarrow d=57.63 \end{gathered}[/tex]

Thereby, using the law of sines:

[tex]\begin{gathered} \frac{d}{\sin90}=\frac{45}{\sin a} \\ \rightarrow d\sin a=45\sin 90\rightarrow\sin a=\frac{45}{d} \\ \rightarrow a=\arcsin (\frac{45}{57.63}) \\ \rightarrow a=51.34 \end{gathered}[/tex]

The angle of the bird's view on the worm is 51.34°

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