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A spring is oscillating vertically according to the equation y=3cos(2t-pi) where y is the displacement in feet and t is time in seconds. At what time will the spring be 2 ft. high? Round your answer to the nearest tenth.

A spring is oscillating vertically according to the equation y3cos2tpi where y is the displacement in feet and t is time in seconds At what time will the spring class=

Respuesta :

we have the equation

[tex]y=3cos(2t-pi)[/tex]

For y=2 ft

substitute in the given equation

[tex]\begin{gathered} 2=3cos(2t-p\imaginaryI) \\ cos(2t-p\mathrm{i})=\frac{2}{3} \end{gathered}[/tex]

Solve for t

using a calculator

2t-pi=0.84

2t=0.84+pi

2t=3.98

t=1.99 -----------> round to one decimal place

t=2.0 sec

The answer is option C

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