Take into account that the momentum p is given by the following formula:
[tex]p=mv[/tex]
where,
p: momentum of the bat = 0.86 kg*m/s
m: mass = ?
v: speed of the bat = 2.9m/s
Solve the previous equation for m, replace the values of v and p, and simplify:
[tex]m=\frac{p}{v}=\frac{0.86\operatorname{kg}\cdot\frac{m}{s}}{2.9\frac{m}{s}}\approx0.30\operatorname{kg}[/tex]
Hence, the mass of the bat is approximately 0.30kg
