Given:
[tex]19=\frac{1}{2}gt^2[/tex]
We will solve the equation to find (t) as follows:
[tex]\begin{gathered} 19=\frac{1}{2}gt^2\rightarrow\times2 \\ 2*19=2*\frac{1}{2}gt^2 \\ 38=gt^2 \\ t^2=\frac{38}{g} \\ \\ t=\sqrt{\frac{38}{g}} \end{gathered}[/tex]
So, the answer will be the first option.
