Respuesta :

Number 1

[tex]\mathrm{Factor}\: x^2-8x+15\colon\quad \mleft(x-5\mright)(x-3)[/tex][tex]\begin{gathered} \\ \mathrm{Factor}\: x^2-8x+15\colon\quad (x-5)(x-3) \\ \text{comparing} \\ x^2-8x+15=\mleft(ax+b\mright)\mleft(cx+d\mright) \\ a=1 \\ b=-5 \\ c=1 \\ d=-3 \end{gathered}[/tex]

The final answer

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