Mass of nickel(ii) nitrate ni(no3)2 must be dissolved is 8.48 gram
It is given that
Volume of solution = 200 ml
Molarity of solution = 0.233 m
We have to find mass of nickel(ii) nitrate ni(no3)2
The concentration of a solute in a solvent (at a definite temperature and pressure condition) may be expressed using the unit molality (m) as per the type of the solution need to be produced. It is defined as the number of moles of the solute present in 1 kg of the solution.
Molarity = moles of solute/volume of solution
0.233 = Given mass/182 x 1000/200
0.233 = Given mass/182 x 5
Given mass = 0.233 x 182/5 = 8.48 gram
Hence, Mass of nickel(ii) nitrate ni(no3)2 must be dissolved is 8.48 gram
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