Given a cyclic quadrilateral PQRS:
As shown:
[tex]\begin{gathered} m\angle Q=66 \\ m\angle P=66 \\ m\angle P+m\angle R=180 \\ m\angle Q+m\angle S=180 \end{gathered}[/tex]
so, as angle P = angle Q
[tex]m\angle R=m\angle S=180-66=114[/tex]
So, the answer will be:
[tex]\begin{gathered} m\angle R=114 \\ m\angle S=114 \end{gathered}[/tex]
