Answer:
The value of x decreases by 5
Explanation:
The initial value of x is:
x = -3m - 2n - 4
If we increase m by 2 and decrease n by 1, we will need to change m by m+2 and n by n-1. So, we can calculate a new value for x, that I will call x₂ as:
[tex]x_2=-3(m+2)-2(n-1)-4[/tex]Now, we can solve for x₂ as:
[tex]\begin{gathered} x_2=-(3\cdot m)-(3\cdot2)-(2\cdot n)-2(-1)-4 \\ x_2=-3m-6-2n+1-4 \\ x_2=-3m-2n-9 \end{gathered}[/tex]Then, we can write -9 as -4 - 5 so:
[tex]x_2=\textcolor{#FF7968}{-3m-2n-4}-5[/tex]Since -3m-2n-4 is equal to x, x₂ is equal to:
[tex]x_2=x-5[/tex]Therefore, if the value of m increases by 2 and the value of n decreases by 1, then the value of x decreases by 5.
