Given:
The function is:
[tex]b(x)=\begin{cases}0.15x,.........................\text{ }x\leq360 \\ 0.10(x-360)+54,\text{ ......}x>360\end{cases}[/tex]
Find-:
How much is the bill for a person who uses 560 KWh in a month
Explanation-:
Uses of 560 KWh in a month
[tex]x=560[/tex]
For x = 560 function apply is:
[tex]b(x)=0.10(x-360)+54.................x>360[/tex]
When x is greater than 360 so function b(x) second use.
[tex]b(x)=0.10(x-360)+54[/tex]
Function value at x = 560 is:
[tex]\begin{gathered} b(x)=0.10(x-360)+54 \\ \\ b(560)=0.10(560-360)+54 \\ \\ b(560)=0.10(200)+54 \\ \\ b(560)=20+54 \\ \\ b(560)=74 \end{gathered}[/tex]
The value at 560 KWh value is $74.
