Respuesta :

Answer:

[tex]\begin{gathered} \begin{equation*} [H^+]=4.36\times10^{-7}M \end{equation*} \\ \begin{equation*} [OH^-]=2.29\times10^{-8}M \end{equation*} \end{gathered}[/tex]

Explanations:

The formula for calculating the pH of a solution is expressed as:

[tex]pH=-log[H^+][/tex]

Given the following parameter

pH =. 6.36

Substitute

[tex]\begin{gathered} 6.36=-log[H^+] \\ log[H^+]=-6.36 \\ [H^+]=10^{-6.36} \\ [H^+]=4.36\times10^{-7}M \end{gathered}[/tex]

Determine the concentration of [OH-] in the solution

[tex]\begin{gathered} [H^+][OH^-]=1.0\times10^{-14} \\ [OH^-]=\frac{1.0\times10^{-14}}{[H^+]} \\ [OH^-]=\frac{1.0\times10^{-14}}{4.36\times10^{-7}} \\ [OH^-]=0.229\times10^{-14+7} \\ [OH^-]=0.229\times10^{-7} \\ [OH^-]=2.29\times10^{-8}M \end{gathered}[/tex]