Solve the triangle by finding the length of DF and the measures of all the angles. For side lengths, round to thenearest tenth. For angles, round to the nearest degres

Answer:
[tex]\begin{gathered} DF=2.99\approx3.0\text{ ft} \\Step-by-step explanation:
To determine the length of DF, we can use the Pythagorean theorem, which is defined by the following diagram and formula:
Then, for DF:
[tex]\begin{gathered} 5^2+DF^2=5.83^2 \\ DF^2=5.83^2-5^2 \\ DF=\sqrt[]{5.83^2-5^2} \\ DF=2.99\approx3.0\text{ ft} \end{gathered}[/tex]Now, to find the angles So, for angle [tex]\begin{gathered} \cos (E)=\frac{5}{5.83} \\ Finally, for angle [tex]\begin{gathered} \text{sin(F)}=\frac{5}{5.83} \\ F=\sin ^{-1}(\frac{5}{5.83}) \\ F=\text{ 59\degree} \end{gathered}[/tex]