Given that:
Number of calculators alpha produces per production shift = 533
Number of calculators beta produces per hour of the prodution shift = 16
Let x denotes the number of hours per production shift.
Then the number of calculators alpha produces per production shift
[tex]=\frac{533}{x}[/tex]
Then the number of calculators produced
[tex]\begin{gathered} =\frac{533}{x}+16 \\ =\frac{533+16x}{x} \end{gathered}[/tex]
Then the desired inequality is
[tex]\frac{533+16x}{x}\ge60[/tex]
Option C is correct.
