In order to find the roots of this quadratic equation, let's identify the coefficients a, b and c from the standard form and use them in the quadratic formula:
[tex]\begin{gathered} ax^2+bx+c=0\\ \\ x^2+3x-6=0\\ \\ a=1,b=3,c=-6\\ \\ \\ \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\ x=\frac{-3\pm\sqrt{9+24}}{2}\\ \\ x_1=\frac{-3-\sqrt{33}}{2}\\ \\ x_2=\frac{-3+\sqrt{33}}{2} \end{gathered}[/tex]
Therefore the answers are A and C.
