Let us firstly represent both cones as images:
To find the volume of a cone, we use the formula
[tex]V=\frac{1}{3}\pi r^2h[/tex]Volume of A
[tex]\begin{gathered} V_A=\frac{1}{3}\times\pi\times3^2\times8 \\ =24\pi \end{gathered}[/tex]Volume of B
[tex]\begin{gathered} V_B=\frac{1}{3}\times\pi\times6^2\times8 \\ V_B=96\pi \end{gathered}[/tex]To find the number of times greater the larger cone is than the smaller cone, we will divide both volumes.
Hence,
[tex]\frac{V_B}{V_A}[/tex]Substituting with the volumes above, we have
[tex]\begin{gathered} \frac{96\pi}{24\pi} \\ =4 \end{gathered}[/tex]Therefore, we can see that the larger cone has 4 times greater volume than the smaller cone.
