The given expression is
[tex]2\sqrt[6]{3}\text{ + 7}\sqrt[6]{3}[/tex]Both terms have the 6th root of 3. Since it is common with both terms, we would factorise. It becomes
[tex]\begin{gathered} \sqrt[6]{3}(2\text{ + 7)} \\ =\text{ }\sqrt[6]{3}\text{ (9)} \\ =\text{ 9}\sqrt[6]{3} \end{gathered}[/tex]