A chemistry student needs 90.0 g of acetone for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that thedensity of acetone is 0.790 g.cm -3. Calculate the volume of acetone the student should pour out.Be sure your answer has the correct number of significant digits.

Respuesta :

The formula for density is

[tex]d=\frac{M}{V}[/tex]

Where d is density, M is mass, and V is volume.

Given

[tex]\begin{gathered} M=90.0g \\ d=0.790g/cm^3 \\ V=\text{?} \end{gathered}[/tex][tex]\begin{gathered} 0.790=\frac{90}{V} \\ \text{cross multiply} \\ 0.790V=90 \\ \text{Divide both sides by }0.790 \\ \frac{0.790V}{0.790}=\frac{90}{0.790} \\ \\ \\ V=\frac{90}{0.790} \\ \\ V=113.92cm^3 \end{gathered}[/tex]

The volume of acetone the student should pour out is

[tex]113.92cm^3[/tex]