In general,
[tex]y=\log _bx\Leftrightarrow x=b^y[/tex]Thus, in our case,
[tex]\begin{gathered} \Rightarrow\log _{27}x=\frac{2}{3} \\ \Leftrightarrow x=27^{\frac{2}{3}} \end{gathered}[/tex]Therefore, simplifying
[tex]\begin{gathered} \Rightarrow x=(27)^{\frac{2}{3}}=(3^3)^{\frac{2}{3}}=3^2=9 \\ \Rightarrow x=9 \end{gathered}[/tex]The answer is x=9
