Let x be the number we are looking for.
Let us go statement by statement so we can find the inequality we want. First we are told "15 minus a number". That would be represented by the expression
[tex]15\text{ -x}[/tex]now, this quantity should be "less than or equal to 8 times that number". So this translates to the expression
[tex]\le8\cdot x[/tex]so if we put together these expressions, we get
[tex]15\text{ -x<=8}\cdot x[/tex]To solve it, we first add x on both sides, so we get
[tex]15\le8x+x[/tex]If we operate on the right, we get
[tex]15\le9x[/tex]Now, we divide both sides by 9, so we get that
[tex]\frac{15}{9}\le x[/tex]which is equivalent to
[tex]\frac{5}{3}\le x[/tex]which mean that any number greater than or equal to 5/3 is a solution for this inequality
