Respuesta :

[tex]y=-x^2-6x-8[/tex]

y-intercept -> x=0

[tex]\begin{gathered} y=-0^2-6\cdot0-8 \\ y=-0-0-8 \\ y=-8 \end{gathered}[/tex]

y-intercept -> x=0, then: (0,-8)

x-intercept -> y=0

[tex]\begin{gathered} y=-x^2-6x-8 \\ \Delta=36-32=4 \\ x=\frac{6\pm\sqrt[]{4}}{-2}=\frac{6\pm2}{-2} \\ x_1=\frac{8}{-2}=-4 \\ x_2=\frac{4}{-2}=-2_{} \end{gathered}[/tex]

x-intercept -> y=0, then: (-2,0) e (-4,0)

vertex

[tex]x_v=-\frac{b}{2a}=-\frac{6}{-2}=-3[/tex]

now find yv

[tex]\begin{gathered} y_v=-(-3)^2-6\cdot(-3)-8 \\ y_v=-9+18-8=9-8=1 \end{gathered}[/tex]

vertex= (-3,1)

The graph below shows the x-intercept and y-intercept

Ver imagen JanettaW661915