Hello!
We have the function:
[tex]f(x)=5^x[/tex]
To solve it, we must replace where's x by -2, look:
[tex]f(-2)=5^{-2}[/tex]
As we have a negative sign, let's write the inverse of it:
[tex](\frac{5}{1})^{-2}\rightarrow(\frac{1}{5})^2[/tex]
So, we'll have:
[tex]\begin{gathered} f(-2)=(\frac{1}{5})^2 \\ \\ f(-2)=\frac{1}{5}\cdot\frac{1}{5} \\ \\ f(-2)=\frac{1\cdot1}{5\cdot5} \\ \\ \boxed{f(-2)=\frac{1}{25}} \end{gathered}[/tex]
Answer:
1/25.
