Given data :
[tex]f(x)\text{ = 3x-1}[/tex][tex]g(x)=\frac{10}{x}[/tex][tex]h(x)=x^2+3[/tex]
a) f(5)
Put x = 5 in the expression of f(x)
[tex]\begin{gathered} f(x)\text{ = 3x-1} \\ f(5)=3(5)-1 \\ f(5)=15-1 \\ f(5)=14 \end{gathered}[/tex]
f(5) = 14
b) g(65)
put x = 65
[tex]\begin{gathered} g(x)=\frac{10}{x} \\ g(65)=\frac{10}{65} \\ g(65)=\frac{2}{13} \end{gathered}[/tex]
g(65) =2/13
c) h(-2)
Put x = -2 in the expression of h(x)
[tex]\begin{gathered} h(x)=x^2+3 \\ h(-2)=(-2)^2+3 \\ h(-2)=4+3 \\ h(-2)=7 \end{gathered}[/tex]
h(-2) = 7
d) f(x) = 20
Put f(x)=20 in the expression of f(x)
[tex]\begin{gathered} f(x)\text{ = 3x-1} \\ 20=3x-1 \\ 3x=20+1 \\ 3x=21 \\ x=\frac{21}{3} \\ x=7 \end{gathered}[/tex]
x = 7
Answer:
a) f(5) = 14
b) g(65)=2/13
c) h(-2)=7
d) x=7
