Respuesta :
SOLUTION
The given area of the right triangle is 140
The base of the right triangle is 28
Using the formula for area of triangle,
[tex]A=\frac{1}{2}bh[/tex]It follows:
[tex]140=\frac{1}{2}\times28\times h[/tex]Solve for h
This gives
[tex]\begin{gathered} 140=14h \\ h=\frac{140}{14} \\ h=10 \end{gathered}[/tex]Therefore the height of the right triangle is 10 units
To find the perimeter the third side of the right triangle will be found using pythagoras theorem
Let the length side be x
Notice that the third side is the hypotenuse, it follows
[tex]\begin{gathered} x^2=28^2+10^2 \\ x=\sqrt{884} \end{gathered}[/tex]Therefore the perimeter is
[tex]\begin{gathered} P=28+10+\sqrt{884} \\ P=38+\sqrt{4\times221} \\ P=38+2\sqrt{221} \end{gathered}[/tex]Therefore the perimeter is:
[tex]P=38+2\sqrt{221}[/tex]