if abcd is dilated by a factor of 1/2 the coordinate of d' would be

The co ordinate of the original coordinate of D is,
[tex]D(2,-2)[/tex]So, the coordinate of the D' will get by multiplying the coordinate by 1/2
[tex]D^{\prime}(\frac{2}{2},-\frac{2}{2})=D^{\prime}(1,-1)[/tex]So, the coordinate of D' is,
[tex]D^{\prime}(1,-1)[/tex]