Figuring out End Behavior, Decreasing and Increasing Interval, and asymptote

Solution
- The function given is:
[tex]f(x)=2^{x+1}-3[/tex]- The best way to understand the solution is to plot the function.
- The plot of the function is given below:
- From the above, we can already make the following deductions depicted below:
- Thus, we can answer the questions asked as follows:
Growth or Decay:
- This is clearly a GROWTH function as it increases from left to right.
- The reason for this increase is the term
[tex]2^{x+1}[/tex]- 2 is the rate of change and since it is greater than 1, the function is increasing. If it were less than 1, it would be decay.
Domain:
- The domain is the set of all x-values for which the function is defined. The function has no breaks from left to right, thus, we can conclude that the domain is
[tex]Domain:(-\infty,\infty)[/tex]Range:
- The range is the set of all y-values for which the function is defined. The function has a minimum value of -3, which is also the Horizontal asymptote of the function. This is because,
[tex]\begin{gathered} \text{ For any exponential function} \\ f(x)=ab^x+c \\ c\text{ is the horizontal asymptote of the function and the minimum value of the function} \\ \\ \text{ Also, if we substitute }x=-\infty\text{ into the function give,} \\ f(x)=2^{-\infty+1}-3 \\ f(x)=\frac{1}{2^{\infty}}-3=0-3=-3 \\ \\ \text{ Thus, when we move further and further towards the left of the graph, the value of} \\ \text{ f\lparen x\rparen becomes -3, just as we established earlier} \end{gathered}[/tex]Y-intercept:
- The y-intercept is simply where the graph crosses the y-axis. This also happens to be where x = 0 in the graph as well.
- From the figure above, we have that the y-intercept is (0, -1)
- But we can also get it from the equation by substituting the value of x = 0 into the function
[tex]\begin{gathered} f(x)=2^{x+1}-3 \\ \text{ put }x=0 \\ f(x)=2^{0+1}-3 \\ f(x)=2-3 \\ f(x)=-1 \\ \text{ Thus, when }x=0,f(x)=-1 \\ \\ \text{ Thus, the y-intercept is }(0,-1) \end{gathered}[/tex]Increasing Interval and Decreasing Interval:
- The interval for which the function is increasing is done by testing values of x and checking out the trend of the function. Usually, we test a negative value, x = 0, a positive value, then, negative and positive infinity.
- But since we have the graph plotted above, we can easily see that the graph is ALWAYS INCREASING over the interval
[tex]x\in(-\infty,\infty)[/tex]End behavior:
- The end behavior of the graph is simply the values of y as x tends to negative and positive infinity.
- Thus, we have:
[tex]\begin{gathered} f(x)=2^{x+1}-3 \\ \text{ Put }x=-\infty, \\ f(-\infty)=2^{-\infty+1}-3 \\ f(-\infty)=-3 \\ \\ \text{ Put }x=\infty \\ f(\infty)=2^{\infty+1}-3 \\ f(\infty)=\infty-3 \\ f(\infty)=\infty \\ \\ \text{ Thus, the End behavior of the function is:} \\ As\text{ }x\to\infty,f(x)\to\infty \\ As\text{ }x\to-\infty,f(x)\to-3 \end{gathered}[/tex]