Given the equation:
[tex]4x-2\sqrt[]{3}\sin \sin x+2\sin \sin x+\sqrt[]{3}-4=0[/tex]
Simplifying the given equation:
[tex]\begin{gathered} 4x-(2\sqrt[]{3}-2)\sin \sin x+\sqrt[]{3}-4=0 \\ 4x-(2\sqrt[]{3}-2)\sin \sin x=4-\sqrt[]{3} \\ 2x-(\sqrt[]{3}-1)\sin \sin x=\frac{(4-\sqrt[]{3})}{2}_{} \end{gathered}[/tex]
